The Bargain Bin Forum

Forum for discussing where to pick up cheap deals

Xbox One Sale Roundup: July 11th, 2017

AuthorMessage
BonnieTheBigVig
Posted on 11 July 17 at 02:48
Twobby said:
thisisgman said:
M+E+H = MEH
You failed algebra didn't you?
Love this...
Notorious V.I.G.
Cornerscout
478,857
Cornerscout
Posted on 11 July 17 at 02:53
I gotta say, as sad as it is that I'm not interested in anything on sale, I sure don't mind saving money several weeks in a row. laugh
Among the best in my state and the world. I blog about it, and I tweet about things I take interest in: @Cornerscout
sanityends
300,668
sanityends
Posted on 11 July 17 at 03:01
I don't get it every week its nothing but whining. If you are not going to buy anything then just do not. There does not need to even be a sale they owe you nothing. Do you go to the store and complain shampoo is not on sale? Of course not. The bitching and complaining is unbelievable.
ThreeHaddock62
Posted on 11 July 17 at 03:06
sanityends said:
I don't get it every week its nothing but whining. If you are not going to buy anything then just do not. There does not need to even be a sale they owe you nothing. Do you go to the store and complain shampoo is not on sale? Of course not. The bitching and complaining is unbelievable.
Especially after a huge sale....Those post add nothing of value to this site- I do appreciate the ones w/ recommendations though.
Hola
Noodles Jr
508,088
Noodles Jr
Posted on 11 July 17 at 03:16, Edited on 11 July 17 at 03:23 by Noodles Jr
Twobby said:
thisisgman said:
M+E+H = MEH
You failed algebra didn't you?
Well if we assume M, E and H are all equal to an arbitrary value A, then the equation can be rewritten as a 3A=A^3. Divide out an A, so 3=A^2, therefore A=±root3. We also know intuitively that M, E and H can be 0 for the equation to check out, but now we also know they can equal root3 and -root3.

We know that if two of the variables are equal to 0, then the equation cannot check out as the MEH would always equal to 0, whereas M+E+H would equal a positive or negative integer. However, if one variable is equal to 0, then there are an infinite number of possibilities, if you let those two variables be the same number, but with separate signs.

If M, E and H are not equal to one another, then we can generalize by saying one of the three variable is larger than the other 2 (we'll say H). Therefore M≤E≤H. With this, we know that 3H≥MEH, and therefore 3≥ME. If 3≥ME, M≠0 and E≠0 then (M,E) can only be (±1,±1), (±1,±2), (±1,±3) (M and E values are interchangeable of course).

By substituting our points into M+E+H=MEH, then we can find that there are no possible values of H that satisfy (1,1), (-1,-1), but there are H values that satisfy (1,2), (1,-2), (-1,-2), (-1,2), (1,3), (1,-3), (-1,-3) and (-1,3), which are 3, 1/3, 3/4, -1/3, 1/2, -2, -1/2 respectively.

These are just a few solutions, and technically, thisisgman is infinitely right. He's infinitely wrong too... but still.
Danzo51196
124,481 124,481 GamerScore
Danzo51196
Posted on 11 July 17 at 03:19
BonnieTheBigVig said:
Twobby said:
thisisgman said:
M+E+H = MEH
You failed algebra didn't you?
Love this...
Guys, stop. I'm out in public laughing like an idiot reading this.
Bigdanzo51169 - Happy Gaming!
billbillbill
513,199
billbillbill
Posted on 11 July 17 at 03:24
LV 1 Blue Slime said:
As a note for Dex... I would say the combat gets quite tedious despite how short of a completion it is so a mere 33% off would not be worth it, in my eyes.
I disagree. I thought DEX was sweet-as.
Old-school RPG with a (for once!) decent cyberpunk story & setting. I'm not gonna talk-up the combat, but then it's not a necessary component by any means. Most all of the game can be completed with little-to-no combat, with multiple routes to the objective.

Basically: It's a simplified, side-scrolling female-led 'Deus Ex' with an open-hub, numerous side-quests and several choice-based, divergent outcomes.

I felt it was decent-enough to grab at full-price. Would recommend to anyone interested in side-scroller 'Metroid-vania's, sci-fi stories or the artwork.
sanityends
300,668
sanityends
Posted on 11 July 17 at 03:32
ThreeHaddock62 said:
sanityends said:
I don't get it every week its nothing but whining. If you are not going to buy anything then just do not. There does not need to even be a sale they owe you nothing. Do you go to the store and complain shampoo is not on sale? Of course not. The bitching and complaining is unbelievable.
Especially after a huge sale....Those post add nothing of value to this site- I do appreciate the ones w/ recommendations though.
As do I ty all for your recommendations of games. Other than that I have no idea why you post anything.
BigWiIIieStyIe
Posted on 11 July 17 at 03:35
Noodles Jr said:
Twobby said:
thisisgman said:
M+E+H = MEH
You failed algebra didn't you?
Well if we assume M, E and H are all equal to an arbitrary value A, then the equation can be rewritten as a 3A=A^3. Divide out an A, so 3=A^2, therefore A=±root3. We also know intuitively that M, E and H can be 0 for the equation to check out, but now we also know they can equal root3 and -root3.

We know that if two of the variables are equal to 0, then the equation cannot check out as the MEH would always equal to 0, whereas M+E+H would equal a positive or negative integer. However, if one variable is equal to 0, then there are an infinite number of possibilities, if you let those two variables be the same number, but with separate signs.

If M, E and H are not equal to one another, then we can generalize by saying one of the three variable is larger than the other 2 (we'll say H). Therefore M≤E≤H. With this, we know that 3H≥MEH, and therefore 3≥ME. If 3≥ME, M≠0 and E≠0 then (M,E) can only be (±1,±1), (±1,±2), (±1,±3) (M and E values are interchangeable of course).

By substituting our points into M+E+H=MEH, then we can find that there are no possible values of H that satisfy (1,1), (-1,-1), but there are H values that satisfy (1,2), (1,-2), (-1,-2), (-1,2), (1,3), (1,-3), (-1,-3) and (-1,3), which are 3, 1/3, 3/4, -1/3, 1/2, -2, -1/2 respectively.

These are just a few solutions, and technically, thisisgman is infinitely right. He's infinitely wrong too... but still.
You just broke the internet lol, I read all that and almost made sense of it lol
Rhhe82
248,530
Rhhe82
Posted on 11 July 17 at 03:40
K4rn4ge said:
If there's only ONE game you buy on sale this week, definitely make it Stardust Galaxy Warriors - only TWO bucks right now & such a great game! Out of the hundreds of indie games I own on Xbox One, Stardust Galaxy Warriors is actually in my personal top 10. Such a steal - dont miss it guys. Also, most of the gamerscore is easy enough but there are a few tricky achs, but nothing too crazy.
I had never heard of this one until now. Took a quick peek to a gameplay video of this and yeah, looks like it's time to add to my everlasting backlog.
GV Loc
359,840
GV Loc
Posted on 11 July 17 at 04:28
Sorry.....the title is wrong. It should be "the xbox one jokes of the week"
Locanu Barosanu
Saint G Man 93
Posted on 11 July 17 at 04:42
Twobby said:
thisisgman said:
M+E+H = MEH
You failed algebra didn't you?
haha you said bra
thisisgman
matdan
667,228
matdan
Posted on 11 July 17 at 04:47
33% off ain't a sale. I only see 4 games on sale and none I would touch, very happy with that. I need a few weeks to clean out my back-log anyway.
Out of the abyss peer the eyes of a demon, Behold the Razgriz, its wings of black sheath!
Saint G Man 93
Posted on 11 July 17 at 04:48
Noodles Jr said:
Twobby said:
thisisgman said:
M+E+H = MEH
You failed algebra didn't you?
Well if we assume M, E and H are all equal to an arbitrary value A, then the equation can be rewritten as a 3A=A^3. Divide out an A, so 3=A^2, therefore A=±root3. We also know intuitively that M, E and H can be 0 for the equation to check out, but now we also know they can equal root3 and -root3.

We know that if two of the variables are equal to 0, then the equation cannot check out as the MEH would always equal to 0, whereas M+E+H would equal a positive or negative integer. However, if one variable is equal to 0, then there are an infinite number of possibilities, if you let those two variables be the same number, but with separate signs.

If M, E and H are not equal to one another, then we can generalize by saying one of the three variable is larger than the other 2 (we'll say H). Therefore M≤E≤H. With this, we know that 3H≥MEH, and therefore 3≥ME. If 3≥ME, M≠0 and E≠0 then (M,E) can only be (±1,±1), (±1,±2), (±1,±3) (M and E values are interchangeable of course).

By substituting our points into M+E+H=MEH, then we can find that there are no possible values of H that satisfy (1,1), (-1,-1), but there are H values that satisfy (1,2), (1,-2), (-1,-2), (-1,2), (1,3), (1,-3), (-1,-3) and (-1,3), which are 3, 1/3, 3/4, -1/3, 1/2, -2, -1/2 respectively.

These are just a few solutions, and technically, thisisgman is infinitely right. He's infinitely wrong too... but still.
W0W
thisisgman
Infamous
690,766
Infamous
Posted on 11 July 17 at 04:58
Came to look at sales - Left disappointed and with a headache.

I also still don't know if M+E+H = MEH laugh
matdan
667,228
matdan
Posted on 11 July 17 at 05:06
thisisgman said:
Noodles Jr said:
Twobby said:
thisisgman said:
M+E+H = MEH
You failed algebra didn't you?
Well if we assume M, E and H are all equal to an arbitrary value A, then the equation can be rewritten as a 3A=A^3. Divide out an A, so 3=A^2, therefore A=±root3. We also know intuitively that M, E and H can be 0 for the equation to check out, but now we also know they can equal root3 and -root3.

We know that if two of the variables are equal to 0, then the equation cannot check out as the MEH would always equal to 0, whereas M+E+H would equal a positive or negative integer. However, if one variable is equal to 0, then there are an infinite number of possibilities, if you let those two variables be the same number, but with separate signs.

If M, E and H are not equal to one another, then we can generalize by saying one of the three variable is larger than the other 2 (we'll say H). Therefore M≤E≤H. With this, we know that 3H≥MEH, and therefore 3≥ME. If 3≥ME, M≠0 and E≠0 then (M,E) can only be (±1,±1), (±1,±2), (±1,±3) (M and E values are interchangeable of course).

By substituting our points into M+E+H=MEH, then we can find that there are no possible values of H that satisfy (1,1), (-1,-1), but there are H values that satisfy (1,2), (1,-2), (-1,-2), (-1,2), (1,3), (1,-3), (-1,-3) and (-1,3), which are 3, 1/3, 3/4, -1/3, 1/2, -2, -1/2 respectively.

These are just a few solutions, and technically, thisisgman is infinitely right. He's infinitely wrong too... but still.
W0W
He is the best math cook in town, only writes in blue ink usually find him in back alleys dealing math equations. 100% pure math equations.
Out of the abyss peer the eyes of a demon, Behold the Razgriz, its wings of black sheath!
MattQuin89
304,738
MattQuin89
Posted on 11 July 17 at 07:38
Tempting to get that Shadow of Mordor GOTY for that price...
WildWhiteNoise
Posted on 11 July 17 at 07:44
Figures. Bought RWBY last week for full price just to have it on sale now. Whoever buying it, you're welcome. wink
XvalgurX
137,971
XvalgurX
Posted on 11 July 17 at 08:18
I have this gut feeling that Shadow of Mordor will be a Game with Gold soon...
MattQuin89
304,738
MattQuin89
Posted on 11 July 17 at 08:33
XvalgurX said:
I have this gut feeling that Shadow of Mordor will be a Game with Gold soon...
Same, that's why I'm resisting the urge to buy! Would make sense with the new one coming out shortly.
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